Handle error for GPG key generation failure

This commit is contained in:
2024-06-05 17:53:30 -04:00
parent a804cf7cff
commit 321bfc5194
+10 -4
View File
@@ -27,21 +27,27 @@ func GpgUIDListGen() []string {
// GpgKeyGen generates a new GPG key and returns the key ID
func GpgKeyGen() string {
gpgGenTempFile := CreateTempFile()
defer os.Remove(gpgGenTempFile.Name())
defer func(name string) {
_ = os.Remove(name) // error ignored; if the file could be created, it can probably be removed
}(gpgGenTempFile.Name())
// create and write gpg-gen file
unixTime := strconv.FormatInt(time.Now().Unix(), 10)
gpgGenTempFile.WriteString(strings.Join([]string{"Key-Type: eddsa", "Key-Curve: ed25519", "Key-Usage: sign", "Subkey-Type: ecdh", "Subkey-Curve: cv25519", "Subkey-Usage: encrypt", "Name-Real: libmutton-" + unixTime, "Name-Comment: gpg-libmutton", "Name-Email: github.com/rwinkhart/libmutton", "Expire-Date: 0"}, "\n"))
_, _ = gpgGenTempFile.WriteString(strings.Join([]string{"Key-Type: eddsa", "Key-Curve: ed25519", "Key-Usage: sign", "Subkey-Type: ecdh", "Subkey-Curve: cv25519", "Subkey-Usage: encrypt", "Name-Real: libmutton-" + unixTime, "Name-Comment: gpg-libmutton", "Name-Email: github.com/rwinkhart/libmutton", "Expire-Date: 0"}, "\n")) // error ignored; if the file could be created, it can probably be written to
// close gpg-gen file
gpgGenTempFile.Close()
_ = gpgGenTempFile.Close() // error ignored; if the file could be created, it can probably be closed
// generate GPG key based on gpg-gen file
cmd := exec.Command("gpg", "-q", "--batch", "--generate-key", gpgGenTempFile.Name())
cmd.Stdout = os.Stdout
cmd.Stderr = os.Stderr
cmd.Stdin = os.Stdin
cmd.Run()
err := cmd.Run()
if err != nil {
fmt.Println(AnsiError + "Failed to generate GPG key: " + err.Error() + AnsiReset)
os.Exit(1)
}
return "libmutton-" + unixTime + " (gpg-libmutton) <github.com/rwinkhart/libmutton>"
}